maximum algorithm slightly simpler
This commit is contained in:
parent
1d75808c0e
commit
24ce1a2339
1 changed files with 11 additions and 11 deletions
22
lines.cpp
22
lines.cpp
|
@ -19,27 +19,25 @@ int main(int argc, char *argv[])
|
|||
std::vector<cv::Point> hull;
|
||||
cv::convexHull(cv::Mat(contours[0]),hull,false);
|
||||
|
||||
int i;
|
||||
int idx[4]={0};
|
||||
// takes the two points that are more distant from the next, ie:
|
||||
// i st distance(hull[i], hull[i+1]) is maximum and 2nd maximum
|
||||
int idx[2]={0};
|
||||
int distance[2]={0};
|
||||
for( i=0; hull.size()>i; i++ )
|
||||
for( unsigned i=0; hull.size()>i; i++ )
|
||||
{
|
||||
cv::Point one=hull[i];
|
||||
cv::Point two=hull[(i+1)%hull.size()];
|
||||
int d=pow(one.x-two.x,2)+pow(one.y-two.y,2);
|
||||
if( d>distance[0] )
|
||||
cv::Point thispoint=hull[i];
|
||||
cv::Point nextpoint=hull[(i+1)%hull.size()];
|
||||
int d=pow(thispoint.x-nextpoint.x,2)+pow(thispoint.y-nextpoint.y,2);
|
||||
if( d>distance[0] ) //the biggest till now
|
||||
{
|
||||
idx[1]=idx[0];
|
||||
idx[3]=(idx[1]+1)%hull.size();
|
||||
idx[0]=i;
|
||||
idx[2]=(idx[0]+1)%hull.size();
|
||||
distance[1]=distance[0];
|
||||
distance[0]=d;
|
||||
}
|
||||
else if( d>distance[1] )
|
||||
else if( d>distance[1] ) // it is the second biggest till now
|
||||
{
|
||||
idx[1]=i;
|
||||
idx[3]=(i+1)%hull.size();
|
||||
distance[1]=d;
|
||||
}
|
||||
}
|
||||
|
@ -61,3 +59,5 @@ int main(int argc, char *argv[])
|
|||
|
||||
return 0;
|
||||
}
|
||||
|
||||
// vim: set noet ts=4 sw=4:
|
||||
|
|
Loading…
Reference in a new issue