Fix time() on 1.8.7

The time() function takes an argument of a timezone, and always returns
time in epoch format. The epoch format is the number of seconds that
have elapsed since January 1, 1970 (midnight UTC/GMT), not counting leap
seconds. This means that it is universally the same regardless of
timezones.

I don't know what the timezone argument is supposed to do, and it is not
documented. So lets just make 1.8.7 work like > 1.8.7
This commit is contained in:
Hunter Haugen 2015-06-04 09:40:52 -07:00
parent f5f72f4b5a
commit ad4ca4cc34
2 changed files with 5 additions and 11 deletions

View file

@ -33,13 +33,14 @@ Will return something like: 1311972653
ENV['TZ'] = time_zone
time = local_time.localtime
result = local_time.localtime.strftime('%s')
ENV['TZ'] = original_zone
else
result = time.localtime.strftime('%s')
end
# Calling Time#to_i on a receiver changes it. Trust me I am the Doctor.
result = time.strftime('%s')
result = result.to_i
return result

View file

@ -7,7 +7,7 @@ describe 'time' do
context 'when running at a specific time' do
before(:each) {
# get a value before stubbing the function
test_time = Time.utc(2006, 10, 13, 8, 15, 11, '+01:00')
test_time = Time.utc(2006, 10, 13, 8, 15, 11)
Time.expects(:new).with().returns(test_time).once
}
it { is_expected.to run.with_params().and_return(1160727311) }
@ -16,13 +16,6 @@ describe 'time' do
it { is_expected.to run.with_params({}).and_return(1160727311) }
it { is_expected.to run.with_params('foo').and_return(1160727311) }
it { is_expected.to run.with_params('UTC').and_return(1160727311) }
context 'when running on modern rubies', :unless => RUBY_VERSION == '1.8.7' do
it { is_expected.to run.with_params('America/Los_Angeles').and_return(1160727311) }
end
context 'when running on ruby 1.8.7, which garbles the TZ', :if => RUBY_VERSION == '1.8.7' do
it { is_expected.to run.with_params('America/Los_Angeles').and_return(1160702111) }
end
it { is_expected.to run.with_params('America/New_York').and_return(1160727311) }
end
end