puppetlabs-stdlib/spec/unit/puppet/parser/functions/delete_spec.rb
Leonardo Rodrigues de Mello c14cbf31e2 bug # 20681 delete() function should not remove elements from original list
The setup: list with 3 elements, delete one:
$test_list = [‘a’, ‘b’, ‘c’]
$test_deleted = delete($test_list, ‘a’)

Print out the elements in ‘test_deleted’:
notify { ‘group_output2’:  withpath => true, name     => “$cfeng::test_deleted”, }
Notice: /Stage[main]/Syslog/Notify[group_output2]/message: bc

Good!  Run-on output shows that ‘a’ was deleted

Print out the elements in ‘test_list’:
notify { ‘group_output1’: withpath => true, name     => “$cfeng::test_list”, }
Notice: /Stage[main]/Syslog/Notify[group_output1]/message: bc

WHAT!?  'a' was deleted from ‘test_list’ as well! Expected abc as output!

This behaviour is confirmed for string, hash and array.
This is fixed on this commit, I had  added two spec tests to cover that cases.

bug #20681 spec test for delete() function.

I had forgot in the last commit the spec test for hash in the
delete function.

bug # 20681 delete() function change aproach.

Instead of rejecting elements from the original list, we use
collection = arguments[0].dup .
then latter we could continue to use delete and gsub! on collection
without impact on original argument.

this is a better solution than the previous one, and works on ruby
1.8.7, 1.9.3 and 2.0.0.

The previous solution does not work on ruby 1.8.7.

delete function remove typo whitespace.

fix typo whitespaces.
2013-09-16 10:19:35 -03:00

56 lines
1.9 KiB
Ruby
Executable file

#! /usr/bin/env ruby -S rspec
require 'spec_helper'
describe "the delete function" do
let(:scope) { PuppetlabsSpec::PuppetInternals.scope }
it "should exist" do
Puppet::Parser::Functions.function("delete").should == "function_delete"
end
it "should raise a ParseError if there are fewer than 2 arguments" do
lambda { scope.function_delete([]) }.should( raise_error(Puppet::ParseError))
end
it "should raise a ParseError if there are greater than 2 arguments" do
lambda { scope.function_delete([[], 'foo', 'bar']) }.should( raise_error(Puppet::ParseError))
end
it "should raise a TypeError if a number is passed as the first argument" do
lambda { scope.function_delete([1, 'bar']) }.should( raise_error(TypeError))
end
it "should delete all instances of an element from an array" do
result = scope.function_delete([['a','b','c','b'],'b'])
result.should(eq(['a','c']))
end
it "should delete all instances of a substring from a string" do
result = scope.function_delete(['foobarbabarz','bar'])
result.should(eq('foobaz'))
end
it "should delete a key from a hash" do
result = scope.function_delete([{ 'a' => 1, 'b' => 2, 'c' => 3 },'b'])
result.should(eq({ 'a' => 1, 'c' => 3 }))
end
it "should not change origin array passed as argument" do
origin_array = ['a','b','c','d']
result = scope.function_delete([origin_array, 'b'])
origin_array.should(eq(['a','b','c','d']))
end
it "should not change the origin string passed as argument" do
origin_string = 'foobarbabarz'
result = scope.function_delete([origin_string,'bar'])
origin_string.should(eq('foobarbabarz'))
end
it "should not change origin hash passed as argument" do
origin_hash = { 'a' => 1, 'b' => 2, 'c' => 3 }
result = scope.function_delete([origin_hash, 'b'])
origin_hash.should(eq({ 'a' => 1, 'b' => 2, 'c' => 3 }))
end
end